Solving the "APuzzleForYou" newsletter puzzle (that one with the 6-colored image)
megatron0000 (16)


Well, I wonder if this is really a tutorial... I haven't truly discovered the secret message -.-
It seems this challenge cannot be solved alone... the rest of the post explains why

Colors ? You mean characters

To start off, the challenge had this little image:

As you know, an image is represented as a list of pixels, each pixel being a point on the image.

Each pixel has 3 values: one for the amount of red color present in that point, another for the amount of green, and the last one for the amount of blue (so called RGB system).

For example, black is {0,0,0} - that is, no color at all - while pure red is {255, 0, 0} and white is {255, 255, 255}. Incidentally, each "color amount" ranges from 0 (minimum) to 255 (maximum), and that is why pure vibrant red is the way I said it is (a pixel like {120, 0, 0} is a not-so-bright red).

Well, the image we want has lots of pixels, but you can visually see that there are only 6 distinct colors. Extracting these colors, they are, in the RGB system (from left to right in the image):

{104, 109, 109}, {46, 116, 117}, {114, 98, 105}, {111, 46, 114}, {101, 112, 108}, {46, 99, 111}

Well, this has everything to do with alphanumeric characters ! As you know, a letter is just a number... in other words, a computer represents a letter by using a number (for example, letter "a" is 97, "b" is 98, ..).

Actually, not only letters, but every character is associated to a number (the hyphen "-" is 45, for instance). It gets somewhat confusing when the character is a digit... like, the digit "0" is represented by the number 48, "1" by 49, etc.

Note: if you are asking yourself why "a" is 97 and not another number, this is the ASCII character set (which defines which number corresponds to which character).

Now we can decode the message contained in the image (if we know ASCII, of course):


Looks like a URL, so I accessed it...

Well, on to the URL

This is what my browser displayed when I accessed

const express = require('express');
const path = require('path')

const app = express();

const flag = process.env.FLAG;

app.get('/', (req, res) => {

app.get('/secret', (req, res) => {
	const username = req.headers['x-replit-user-name'];
	if (!username) {
		res.send(`I don't know who you are :(`)

	const index = username
		.reduce((a, v) => a + v.charCodeAt(), 0)
	res.send(`hey ${username}, ${flag[index % flag.length]}`)


Hum, looks like a webserver written in Node.js. I accessed the / route, so it returned me the contents of the index.js file of the server.

But you see there is a route for /secret... so, accessing it (, I got:

hey megatron0000, i

Well, not surprising, since the logic that defined this result is contained in the code of the server I just showed.

If you speak javascript, you will have noticed that the server is just summing up every character of your username (remember ? every character is associated to a number, so you can "add characters") and using the result to display only one character of the string variable flag of the server (visible in the server code above). My username got me that letter i on the end of my message hey megatron0000, i

What is the flag ?

So, I want to know what is the full string flag so badly that you see this tutorial here >_<

The thing is, since each unique username yields a single character of the flag (mine was the letter i), the only way to know what all the characters of the flag are is to just have a lot of users access the same URL I did.

If you are curious, access it and tell everyone which letter you got... hopefully eventually we will have all the letters

big edit: Trying to forge a request to that URL with a custom x-replit-user-name header (the request header through which the server knows your username) does not work ¬¬' Probably this header is created by the servers themselves based on your session data, so they know if you are who you affirm you are

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megatron0000 (16)

@mat1 I take it you opened a hole in their auth (actually, you found a hole there)?

You, sir, are dangerous O_O (that was intended as a compliment, by the way)